Need Help Creating PHP UPDATE & Delete Statements

**King_Jay16** · Mar 13, 2012, 12:06 AM

Hey guys I need help creating a PHP function/statement to update a record in my database and also one to delete a record from the database.

I already got the add record to the database working.

HTML FORM CODE

HTML Code:

<head>
<title>Change Person</title>
</head>
<body>

<form action="change_person.php">
ID: <input type="text" name="id" />
Name: <input type="text" name="name" />
Gender: <input type="text" name="gender" />
Age: <input type="text" name="age" />
<input type="submit" />
</form>

</body>

HTML Code:

<head>
<title>Add Person</title>
</head>
<body>

<form action="add_person.php">
ID: <input type="text" name="id" />
Name: <input type="text" name="name" />
Gender: <input type="text" name="gender" />
Age: <input type="text" name="age" />
<input type="submit" />
</form>

</body>

PHP CODE ADD PERSON

PHP Code:


<HTML>

<HEAD>

    <TITLE> Add Person</TITLE>

</HEAD>

<BODY>



<?php

include('connect.php');    

$id=$_GET['id'];

$name=$_GET['name'];

$gender=$_GET['gender'];

$age=$_GET['age'];



$query="INSERT INTO person (id,Name,Gender,Age) VALUES ('$id','$name','$gender','$age')";



 if(pg_query($query)) {

        echo "User successfully added";

   

     }

    else {

         echo " ERROR: Duplicate Person";

         

    }



?>



</BODY>

</HTML>

I messed around trying to get the delete and update function working but not getting anywhere. Can anyone provide some help.

**King_Jay16** · Mar 13, 2012, 10:26 AM

any takers on this on?

Yung_Jah · Mar 13, 2012, 08:40 PM

Your way of coding may be the shorter version I guess....but learning it at school now....for the last coding that you posted....in mine I have something like this...I didnt copy all the coding

<?php

$fname = $_POST["fname"];
$lname = $_POST["lname"];
$email = $_POST["email"];
$address = $_POST["address"];
$parish = $_POST["parish"];
$homephone = $_POST["homephone"];
$mobilephone = $_POST["mobilephone"];

$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Sorry but i could not connect to your server: ' . mysql_error());
}
mysql_select_db("applicants");

mysql_query("INSERT INTO students (Fname, Lname, Email, Address, Parish, Home, Mobile)
VALUES ('$fname','$lname','$email','$address','$parish',' $homephone','$mobilephone')");

If you notice where [mysql_select_db("applicants");] is.....applicants is the name of the database....while students is the name of the table. Dont see the name of the database in yours.

Where I have [ mysql_query("INSERT INTO ] that ends with another bracket at the end if you notice...dont know if it makes a difference...though you only have [ $query="INSERT ]. Maybe thats where you are having the issue.

But for your coding, maybe this video may help you....http://www.youtube.com/watch?v=mn0ucCuNOTI. At first I started to use this....but for my assignment, I got lost along the way.

Hope this will help.

**King_Jay16** · Mar 13, 2012, 10:51 PM

Originally Posted by Yung_Jah

Your way of coding may be the shorter version I guess....but learning it at school now....for the last coding that you posted....in mine I have something like this...I didnt copy all the coding

If you notice where [mysql_select_db("applicants");] is.....applicants is the name of the database....while students is the name of the table. Dont see the name of the database in yours.

Where I have [ mysql_query("INSERT INTO ] that ends with another bracket at the end if you notice...dont know if it makes a difference...though you only have [ $query="INSERT ]. Maybe thats where you are having the issue.

But for your coding, maybe this video may help you....http://www.youtube.com/watch?v=mn0ucCuNOTI. At first I started to use this....but for my assignment, I got lost along the way.

Hope this will help.

thanks will test the later and keep it as a reference... I however met with my Professor and got it sorted out. See the code below

Change/Update Record

HTML Code:

<HTML>
<HEAD>
    <TITLE> Change Person</TITLE>
</HEAD>
<BODY>

<?php

	
include("connect.php");
	$id=$_GET["id"];
	$name=$_GET["name"];
	$age=$_GET["age"];
	$gender=$_GET["gender"];
	
	$query="UPDATE person SET name= $1, gender= $2, age=$3  WHERE id=$4";
	pg_query_params($query,array($name,$gender,$age,$id));
	
?>

</BODY>
</HTML>

As for the name of the database and connection items, those are included in the connect.php file, that way you only update your credentials etc in one place

Yung_Jah · Mar 15, 2012, 04:24 AM

Cool....good to know you got through. There is always a shorter version to do things.

Yung_Jah · Mar 20, 2012, 09:37 PM

But I am still puzzles...I dont see the name of the database....I am only seeing the name of the table which is "person"

**Dre'** · Mar 21, 2012, 05:56 AM

Originally Posted by Yung_Jah

But I am still puzzles...I dont see the name of the database....I am only seeing the name of the table which is "person"

The database name would be located in the connect.php file. like King_Jay16 previously stated.

@King_Jay16

Code:

......
//Delete from database
	$query_delete="DELETE FROM person WHERE id='$ID' ";
	mysql_query($query_delete);......

or
$query_delete="DELETE FROM person WHERE id=$4 ";
	pg_query_params($query_delete(array($name,$gender,$age,$id));

and that would be your delete based on the last data shown.

if both operations where happening on a form then you would set it to a specific button using IF conditions

if ( isset($_POST['Delete_Details']))
{

}

'Delete_Details' would be the name of the button the user needs to press.

Yung_Jah · Mar 21, 2012, 09:37 AM

Oh zeen...respect still.

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