Your insights needed!

[carey]

#include <stdio.h>

int main()
{
  int array[10]={1,2,2,3,4,4,5,6,7,7}
  
  ...
}

How do you replace duplicate elements? How do you prompt the user to replace that specific array address?

[recursion]

What would you like to replace them with? Will the array always be sequential?

[carey]

So lets say the array was assembled from user input. How do you prune the array during the loading process, when the user is actually keying in the data?

Where I am at right now:

/*Program contains an array of size 20. Allow user to load array.
Ensure no duplication. Use at least 2 functions to achieve goal.
Display content of array with location.*/
#include <stdio.h>
#define SIZE 20

int main(void)
{
	int array[SIZE];
	int c;
	for (c=0; c<SIZE; c++)
	{
		printf("Enter an integer:\n");
		/* something here to check if input is same as previous*/
		scanf("%i",&array[c]);
	}
	printf("%s\t\t%s\n","Array subscript","Value");
	for(c=0; c<SIZE; c++)
	{
		printf("%8d\t\t%2d\n",c,array[c]);
	}
}

[recursion]

The %i in scanf should be %d.

You'd really want to check after scanf as well since that's where you read the number.

Instead of a for loop you could use a while loop and only proceed if the number read is not equal to array[i-1]. You might therefore want to use a temporary variable to hold the number and check it before assigning it to the array. Also, watch out for index 0 since there is no index at -1

[carey]

The %i in scanf should be %d

These are identical according to documents.

You'd really want to check after scanf as well since that's where you read the number.

Doesn't scanf assign the value to the variable right away?

Instead of a for loop you could use a while loop and only proceed if the number read is not equal to array[i-1].

We are instructed that the 'for loop' is the same mechanism, but cleaner because it's a closed function(italicized words mine)

You might therefore want to use a temporary variable to hold the number and check it before assigning it to the array. Also, watch out for index 0 since there is no index at -1

So the idea is to store the first input into a variable, pass it to the array, then compare every other input afterwards?

[recursion]

These are identical according to documents.

I was wondering about that, didn't check. Cool

Doesn't scanf assign the value to the variable right away?

Yes it does. I was saying that the comment /* something here to check if input is same as previous*/ (or code that should replace it) should be after you've read the variable.

We are instructed that the 'for loop' is the same mechanism, but cleaner because it's a closed function(italicized words mine)

They can both be written to behave the same way. What I was suggesting was the removal of the increment on every iteration, since if it is repeated you might not want to move down the array.

So the idea is to store the first input into a variable, pass it to the array, then compare every other input afterwards?

Store the first in the array, then for the others, store them in a variable and compare with the previous index before inserting them.

[carey]

They can both be written to behave the same way. What I was suggesting was the removal of the increment on every iteration, since if it is repeated you might not want to move down the array.

Store the first in the array, then for the others, store them in a variable and compare with the previous index before inserting them.

Ok, I think I understand. Instead of using a for loop, use a process to set the first value, then use a function to compare and insert the rest. Going to get to it in a few. Will post what I come up with.

[carey]

Still stuck. I want to:
1. watch for duplicates in the array
2. prompt the user to replace the duplicate

[wiel]

#include <stdio.h>
#include <conio.h>

#define SIZE 10;

void function(int);
int array[SIZE],c=0,x,val;

int main()
{
	
	
	for (c=0; c<SIZE; c++)
	{
		printf("Enter an integer:\n");
                scanf("%d",&val);
                function(val); 
	}
	printf("%s\t\t%s\n","Array subscript","Value");
	for(c=0; c<SIZE; c++)
	{
		printf("%8d\t\t%2d\n",c,array[c]);
	}
 getch();
 return 0;
}

void function(int val)
{
	for(x=0;x<SIZE;x++) /* something here to check if input is same as previous*/
	{
          if (array[x]==val)
          {
           printf("enter a new value");
           scanf("%i",&array[x]);
          } 
	} 


}

[carey]

That seems like it!
I adapted it a bit.

I think I better post my entire source code:

/*Program contains an array of size 20. Allow user to load array.
Ensure no duplication. Use at least 2 functions to achieve goal.
Display content of array with location.*/
#include <stdio.h>
#define SIZE 20 //this is the array size originally

void table_head(void);// for output table
int dup_check();// duplication checker
int array[SIZE];

int main(void)
{

	int c;// for incrementing
	int check,newone;

	//for (c=0; c<SIZE; c++)
	c=0;
	while (c<SIZE)
	{
		printf("Enter an integer:\n");
		if (c==0)
		{
			scanf("%i",*array);//first entry not duplicate
			continue;
		}
		scanf("%i",&check);
		dup_check();
		array[c]=newone;
		c++;
	}

	table_head();
	for(c=0; c<SIZE; c++)
	{
		printf("%8d\t\t%2d\n",c,array[c]);
	}
}

void table_head(void)
{
	printf("%s\t\t%s\n","Array subscript","Value");
}

int dup_check(int check)//Thanks to wiel on Techjamaica.com forums
{
	int x;
	int newone;
	for(x=0; x<SIZE; x++) /* something here to check if input is same as previous*/
	{
		if (array[x]==check)
		{
			printf("You already entered %i.\nEnter another integer:\n",check);
			scanf("%i",&newone);
			return newone;
		}
		else
			array[x]=check;
	}
	
}

So far it doesn't run.