Maximus
October 30, 2004, 11:13 AM
hey any of you guys know how to subnet. Im actually do a network switching course and learning how to subnet but heres my problem i was given a question with a class B adress to generate 500 hosts just for praactice but i wasnt told how many subnets were needed so hers what i did so far
converted the ip address to binary 182.10.0.0(dec)
10110110 . 00001010 . 00000000 . 00000000(bin)
(3rd octet)
11111110 . 00000000
i used the first seven bits of the of the third octet and used the formual 2^n-2. 2 to the power of n minus two n being the number of bits used which would give me 128-2 subnet ids and a total 0f 512-2 host ids which actually makes 510 usable host ids i then need to determine the subnet mask as the default subnet mask would be 255.255.0.0 i determined the subnet mask by counting all the used bits in the third octet this would give me a masks of 255.255.254.0
i determined the netid multiplyer by subtracting the interesting octet which is the 3rd in this case from the total amount of bit in any given octet which is 256. so 256-254= 2
now that i have the id multipyer my ids would start from
2
4
6
8
10
to253
my problem is how do i display the net work ids after all of this im a bit confused right now i gave it a shot though
tell mi if these are correct hear are the first three
182.10.2.0
182.10.4.0
182.10.6.0
or should the ids in between these be shown to
thanks in advance for your assistance
converted the ip address to binary 182.10.0.0(dec)
10110110 . 00001010 . 00000000 . 00000000(bin)
(3rd octet)
11111110 . 00000000
i used the first seven bits of the of the third octet and used the formual 2^n-2. 2 to the power of n minus two n being the number of bits used which would give me 128-2 subnet ids and a total 0f 512-2 host ids which actually makes 510 usable host ids i then need to determine the subnet mask as the default subnet mask would be 255.255.0.0 i determined the subnet mask by counting all the used bits in the third octet this would give me a masks of 255.255.254.0
i determined the netid multiplyer by subtracting the interesting octet which is the 3rd in this case from the total amount of bit in any given octet which is 256. so 256-254= 2
now that i have the id multipyer my ids would start from
2
4
6
8
10
to253
my problem is how do i display the net work ids after all of this im a bit confused right now i gave it a shot though
tell mi if these are correct hear are the first three
182.10.2.0
182.10.4.0
182.10.6.0
or should the ids in between these be shown to
thanks in advance for your assistance